A rocket is launched straight up from the earth’s surface at a speed of 1.70×104 m/s.?
A rocket is launched straight up from the earth’s surface at a speed of 1.70×104 m/s.
What is its speed when it is very far away from the earth?
Thank you!!
Initial Kinetic Energy (KE) of the rocket = 1/2*mv^2 = (1.445 x 10^8) * m
Initial potential energy (PE) = -GMm / R
= – (6.67 * 10^-11) (6 * 10^24) m / (6.4 * 10^6)
= (- 6.25 * 10^7) * m
Total initial energy = KE + PE = (8.2 x 10^7 )* m
From Conservation of Energy,
Total Initial Energy = Total Final Energy
So
Total Final Energy = 8.2 x 10^7 * m
Final PE = 0 (Put r = infinity in the expression for PE)
So
Final KE = 8.2 * 10^7 * m
1/2*m*v^2 = 8.2 * 10^7 * m
v = 1.28 x 10^4 m/s
Hope your enjoying Clemson, just did the problem myself (;
Source(s): student
A rocket is launched straight up from the earth’s surface at a speed of 1.90×104 m/s .