If the sailor’s eye level is 14 ft about the water, how far is the ship from the rocks? (physics)?

A lighthouse that rises 49 feet above the surface of the water sits on a rocky cliff that extends 19 feet from the base. A sailor on the deck of a ship sights the top of the lighthouse at an angle of 30.0 degrees about the horizontal.

If the sailor’s eye level is 14 feet above the water, how far is the ship from the rocks?

(I’ve worked this 5 times and I still haven’t got the right answer PLEASE HELP thanks!!!)

The difference between them is 35 ft. (49-14)

The opposite end of the right triangle that the line up forms is 35 ft. The adjacent end is x ft.

(opposite end)/ adjacent end = tangent (30 degrees)

tangent 30 degrees = 1/2

35 ft/x = 1/2

x= 70 ft.

If the sailor’s eye level is 14 ft above the water, how far is the ship from the rocks?