## Find the area of the part of the plane 5x + 3y + z = 15 that lies in the first octant.

Find the surface area of the part of the plane 5x+3y+z=15 that lies in the first octant’? The surface area equals ∫∫ √(1 + (z_x)^2 + (z_y)^2) dA = ∫∫ √(1 + (-5)^2 + (-3)^2) dA, since z = 15 – 5x – 3y = √35 ∫∫ dA = √35 * (Area enclosed by the … Read more