What is the total rate at which electrical energy is dissipated in the 5.0−Ω resistor?

Consider the circuit of the figure (Figure 1) .

What is the total rate at which electrical energy is dissipated in the 5.0−Ω resistor?

What is the total rate at which electrical energy is dissipated in the 9.0−Ω resistor?

What is the power output of the 16.0-V battery?

At what rate is electrical energy being converted to other forms in the 8.0-V battery?

They are all in series, so the two batteries add up to 8 volts (since the polarities are opposiet) and the R’s add up to 14+3 = 17 Ω.

Current is therefore 8/17 = 0.471 amps

and power in the 5 Ω is P = I²R = 0.471²5 = 1.107 watts

in the nine it is 0.471²9

in the 16v battery it is 0.471 x 16

in the 8v battery it is 0.471 x 8

What is the total rate at which electrical energy is dissipated in the 5.0−ω resistor?