What pressure will 14.0 g of CO exert in a 3.5 L container at 75°C?
14 g of Co = 14/28 = 0.5 mole. so n=0.5, R=0.082atm L mol-1 K-1, T= 273+75 =348K, V=3.5 L
so applying gas equation, PV=nRT,
P= 0.5X0.082 X348/3.5 =4.0765 atm.
What pressure will 14.0 g of co exert in a 3.5 l container at 75°c?